Re: precision in roots()

[Peter Bruin <P.Bruin@warwick.ac.uk>]

Hello Loïc,

>> In result %5, the real part does reflect the precision parameter, but
>> the imaginary part seems to be limited by the GP precision.  Is this
>> intended?  (It also affects nfinit(), bnfinit() etc.)
>
>     No, it has the required precision but is *printed* accorded to the GP
>   precision. Try
>
> precision(imag(%5[1]))

Ah, I see, you're completely right.  I somehow forgot that the GP
default precision is also used to truncate the output precision.

Thanks,

Peter