Aurel . Page on Tue, 20 Jan 2015 11:21:43 +0100 |
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Re: Mixing variables in Mod expressions |
Aurel Quoting John Cremona <john.cremona@gmail.com>:
The link does explain the first output in a way that makes sense to me: the two moduli are coprime so the common quotient is mod 1 hence 0. For a beginner, a run-time error might be more informative though, along the lines of "invalid summands" or "incompatible moduli" -- but I think that the policy might be to always allow addition between objects of the same type? John On 20 January 2015 at 09:53, Karim Belabas <Karim.Belabas@math.u-bordeaux.fr> wrote:Dear John, * John Cremona [2015-01-20 10:20]:I am trying to understand the following. The answer might well be something like "if you try to do something stupid then you must expect a stupid answer" ? Mod(x,x^2-3) + Mod(x,x^2-5) %1 = 0This is by design. And (IMHO) impossible to fix to get "expected" results (e.g. POLMOD variables being treated as "mute" variables). Does the following FAQ explain the situation in a satisfactory way ? http://pari.math.u-bordeaux1.fr/faq.html#modular-- but I was pretending to be a student trying to find the polynomial satisfied by sqrt(3)+sqrt(5) and doing what seemed natural.There are various ways to achieve this: (10:42) gp > algdep(sqrt(3)+sqrt(5), 4) %1 = x^4 - 16*x^2 + 4 (10:43) gp > polcompositum(x^2-3, x^2-5) %2 = [x^4 - 16*x^2 + 4] (10:43) gp > rnfequation(y^2-3, x^2-5) %3 = x^4 - 16*x^2 + 4 [ all 3 methods can break in various ways, but they can all be made to work (provably) with extra effort ]This version works: ? Mod(x,x^2-3) + Mod(y,y^2-5) %2 = Mod(x + Mod(y, y^2 - 5), x^2 - 3) ? a = Mod(x,x^2-3) + Mod(y,y^2-5) %3 = Mod(x + Mod(y, y^2 - 5), x^2 - 3) ? a^2-8 %4 = Mod(Mod(2*y, y^2 - 5)*x, x^2 - 3) ? (a^2-8)^2 %5 = Mod(Mod(60, y^2 - 5), x^2 - 3) ? (a^2-8)^2-60 %6 = 0 but that is not the point; result %1 is surely going to confuse people.Cheers, K.B. -- Karim Belabas, IMB (UMR 5251) Tel: (+33) (0)5 40 00 26 17 Universite de Bordeaux Fax: (+33) (0)5 40 00 69 50 351, cours de la Liberation http://www.math.u-bordeaux1.fr/~kbelabas/ F-33405 Talence (France) http://pari.math.u-bordeaux1.fr/ [PARI/GP] `