| Ruud H.G. van Tol on Thu, 17 Nov 2022 00:42:00 +0100 |
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| A006899(n) |
For https://oeis.org/draft/A006899
"Numbers of the form 2^i or 3^j."
I created this code:
{
a(n)=
my
( i0= logint(3^(n-1), 6)
, i= logint(3^ n , 6)
);
if
( i > i0
, 2^i
, my(j= logint(2^n, 6));
3^j
)
}
which I'm quite happy with,
but I might be wrong!
-- Ruud