Ruud H.G. van Tol on Tue, 15 Jul 2025 11:41:49 +0200


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Re: question on solutions of rational versus integer ternary quadratics



On 2025-07-14 22:11, American Citizen wrote:
I am working with the following conic and 2 ternary quadratics

conic =  [261/5, -3481/50, 261/5, -1739/100, -1739/100, -1]
T9Q([x,y,z]) = 261/5*x^2 + (-3481/50*y - 1739/100*z)*x + (261/5*y^2 - 1739/100*z*y - z^2) T9Z([x,y,z]) = 5220*x^2 + (-6962*y - 1739*z)*x + (5220*y^2 - 1739*z*y - 100*z^2)

T9Q( x, y, x ) = conic * [ x^2, x*y, y^2, x*z, y*z, z^2 ]~

-- Ruud