| Bill Allombert on Tue, 10 Feb 2026 17:35:51 +0100 |
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| Re: question on recovering a single parameter from a minimal model elliptic curve |
On Mon, Feb 09, 2026 at 04:50:06PM -0800, American Citizen wrote: > Hi: > > I have an elliptic curve (not minimal model) defined for a rational number > r. > > > ? E1_min(r)[1..5] > > %14 = [0, -1, 0, -274977905984, -55446464208117696] > Given the minimal model E1_min coefficients, how can I recover r = 33/29? Use the j-invariant, it is the same for E1 and E1_min. nfroots(,numerator(E1(x).j - E1_min(33/29).j)) %412 = [-31/2,-33/29,-29/33,-2/31,2/31,29/33,33/29,31/2]~ Then you test whether (E.c6*Emin.c4)/(E.c4*Emin.c6) is a perfect square to eleminate the wrong twists. Cheers, Bill.